ChemCalc
You entered: C23H27N4O2F
The formula is: C23H27FN4O2
Molecular weight: 410.491383
Monoisotopic mass: 410.211804
Elemental analysis of C23H27FN4O2:
| Element | Number | Percentage |
|---|---|---|
| C | 23 | 67.298124 |
| H | 27 | 6.629708 |
| F | 1 | 4.62821 |
| N | 4 | 13.648715 |
| O | 2 | 7.795243 |
Isotopic distribution