ChemCalc
You entered: C23H27N4O3F
The formula is: C23H27FN4O3
Molecular weight: 426.490783
Monoisotopic mass: 426.206719
Elemental analysis of C23H27FN4O3:
| Element | Number | Percentage |
|---|---|---|
| C | 23 | 64.773498 |
| H | 27 | 6.381001 |
| F | 1 | 4.454587 |
| N | 4 | 13.136697 |
| O | 3 | 11.254217 |
Isotopic distribution